I know how much you enjoyed my last 9 digit number puzzle so I decided to post another one. This time the rules go as follows.
Find a number consisting of 9 digits where each of the digits appears once and once only.
This number needs to be such that the first digit in the number is divisible by 1.
The 1st and 2nd digits together divide by 2, e.g. if the first 2 digits are 1 and 2, 12 will divide by 2.
The 1st, 2nd and 3rd digits together divide by 3 e.g. 246 will divide by 3.
This keeps going until the 9th digit has to divide by 9.
What is the 9 digit number?
The solution will be in my next post!
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